[OZAPRS] HF Mobile beacon times
Chris Hill
chris.hill at crhtelnet.com.au
Thu Jul 8 01:38:06 EST 2004
Hi Richard,
>In the example above VK3BYD-14 has a 33% chance of being heard by
VK4DMI-4
>and a 50% chance of being heard by VK4AH-4. So he has a 83% chance of
being
>heard. The WA station has a 50% chance and the NT station has a 33%
chance.
Just a fine point on probabilities...
If
the probability of being heard by station 1 = P1 = 50%
and
the probability of being heard by station 2 = P2 = 33%
Then
the probability of being heard by both stations = Pall = P1 * P2 = 0.5 *
0.33 = 0.165
and
the probability of not being heard at all = P! = P!1 * P!2 = 0.5 * 0.67 =
0.33
and
the probability of being heard by one or both stations = 1 - P! = 0.67
In other words, the station mentioned above has a 67% chance of being
heard,
not an 83% chance.
73,
Chris vk6kch
_______________________________________________
ozaprs mailing list
ozaprs at marconi.ics.mq.edu.au
http://marconi.ics.mq.edu.au/cgi-bin/mailman/listinfo/ozaprs
More information about the Ozaprs
mailing list